例1
代码如下
create function f_split(@SourceSql varchar(8000),@StrSeprate varchar(10)) returns @temp table(a varchar(100)) --实现split功能 的函数 --date :2003-10-14 as begin declare @i int set @SourceSql=rtrim(ltrim(@SourceSql)) set @i=charindex(@StrSeprate,@SourceSql) while @i>=1 begin insert @temp values(left(@SourceSql,@i-1)) set @SourceSql=substring(@SourceSql,@i+1,len(@SourceSql)-@i) set @i=charindex(@StrSeprate,@SourceSql) end if @SourceSql<>'' insert @temp values(@SourceSql) return end select * from dbo.f_split('1,2,3,4',',') a -------------------- 1 2 3 4 (所影响的行数为 4 行)
例2
代码如下
--SQL Server Split函数 --Author:zc_0101 --说明: --支持分割符多字节 --使用方法 --Select * FROM DBO.F_SQLSERVER_SPLIT('1203401230105045','0') --select * from DBO.F_SQLSERVER_SPLIT('abc1234a12348991234','1234') --Select * from DBO.F_SQLSERVER_SPLIT('ABC',',') CREATE FUNCTION F_SQLSERVER_SPLIT(@Long_str varchar(8000),@split_str varchar(100)) RETURNS @tmp TABLE( ID inT IDENTITY PRIMARY KEY, short_str varchar(8000) ) AS BEGIN DECLARE @long_str_Tmp varchar(8000),@short_str varchar(8000),@split_str_length int SET @split_str_length = LEN(@split_str) IF CHARINDEX(@split_str,@Long_str)=1 SET @long_str_Tmp=SUBSTRING(@Long_str,@split_str_length+1,LEN(@Long_str)-@split_str_length) ELSE SET @long_str_Tmp=@Long_str IF CHARINDEX(REVERSE(@split_str),REVERSE(@long_str_Tmp))>1 SET @long_str_Tmp=@long_str_Tmp+@split_str ELSE SET @long_str_Tmp=@long_str_Tmp IF CHARINDEX(@split_str,@long_str_Tmp)=0 Insert INTO @tmp select @long_str_Tmp ELSE BEGIN WHILE CHARINDEX(@spl(www.cainiaojc.com)it_str,@long_str_Tmp)>0 BEGIN SET @short_str=SUBSTRING(@long_str_Tmp,1,CHARINDEX(@split_str,@long_str_Tmp)-1) DECLARE @long_str_Tmp_LEN INT,@split_str_Position_END int SET @long_str_Tmp_LEN = LEN(@long_str_Tmp) SET @split_str_Position_END = LEN(@short_str)+@split_str_length SET @long_str_Tmp=REVERSE(SUBSTRING(REVERSE(@long_str_Tmp),1,@long_str_Tmp_LEN-@split_str_Position_END)) IF @short_str<>'' Insert INTO @tmp select @short_str END END RETURN END
例3
Sql2000andSql2005实用的Split函数
代码如下
sql2000 CREATE FUNCTION [dbo].[splitstring_array] ( @string nvarchar(4000),@split char(1) ) RETURNS @array table ( oneStr nvarchar(100) ) AS BEGIN declare @v_code varchar(60) --zell 2006-05-26 --set @string = replace(@string,' ',@split) --set @string = replace(@string,',',@split) while len(@string) > 0 begin if charindex(@split,@string,1) != 0 begin set @v_code = substring(@string,1,charindex(@split,@string,1)-1) set @string = substring(@string,charindex(@split,@string,1)+1,len(@string)) end else if charindex(@split,@string,1) = 0 begin set @v_code = @string set @string = '' end insert into @array(onestr) values(@v_code) end RETURN END sql2005 CREATE function [dbo].[func_splitid] (@str varchar(max),@split varchar(10)) RETURNS @t Table (c1 nvarchar(100)) AS BEGIN DECLARE @x XML SET @x = CONVERT(XML,'<items><item id="' + REPLACE(@str, @split, '"/><item id="') + '"/></items>') INSERT INTO @t SELECT x.item.value('@id[1]', 'nvarchar(100)') FROM @x.nodes('//items/item') AS x(item) RETURN END
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