Android XML数据解析简单示例

1、创建XML数据

在android工程目录中res/目录下创建raw文件夹，在raw文件夹内创建data.xml。

<?xml version="1.0" encoding="utf-8"?>

<data>

    <class>

        <c studentNum="1">Android</c>

        <c studentNum="2">IPhone</c>

    </class>

</data>

2、XML解析代码

import java.io.IOException;

import java.io.InputStream;

import javax.xml.parsers.DocumentBuilder;

import javax.xml.parsers.DocumentBuilderFactory;

import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;

import org.w3c.dom.NamedNodeMap;

import org.w3c.dom.Node;

import org.w3c.dom.NodeList;

import org.xml.sax.SAXException;
import android.os.Bundle;

import android.app.Activity;
public class MainActivity extends Activity {
 @Override

 protected void onCreate(Bundle savedInstanceState) {

  super.onCreate(savedInstanceState);

  setContentView(R.layout.activity_main);

  

  InputStream is = getResources().openRawResource(R.raw.data);

  try {

   byte[] bytes = new byte[is.available()];

   is.read();

   String XMLStr = new String(bytes,"utf-8");

   is.reset();

   System.out.println(XMLStr);

   

   DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder();

   Document doc = builder.parse(is);

   

   Node node = doc.getFirstChild();

   System.out.println("第一个子节点"+node.getNodeName());

   NodeList list = doc.getElementsByTagName("c");

   NamedNodeMap map;

   for(int i = 0; i < list.getLength(); i++)

   {

    node = list.item(i);

    map = node.getAttributes();

    System.out.println(node.getTextContent()+"  studentNum  "+map.getNamedItem("studentNum").getNodeValue());

   }

   

  } catch (IOException e) {

   // TODO Auto-generated catch block

   e.printStackTrace();

  } catch (ParserConfigurationException e) {

   // TODO Auto-generated catch block

   e.printStackTrace();

  } catch (SAXException e) {

   // TODO Auto-generated catch block

   e.printStackTrace();

  }

 }

}