long long int llround(double x); long long int llround(float x); long long int llround(long double x); long long int llround(T x); //为整型
llround()函数采用单个参数,并返回long long int类型的值。此函数在<cmath>头文件中定义。
llround()函数将单个参数值取整。
llround()函数返回最接近x的整数值,中间情况下从零舍入。返回的值是long long int类型。
#include <iostream> #include <cmath> using namespace std; int main() { long long int result; double x = 11.16; result = llround(x); cout << "llround(" << x << ") = " << result << endl; x = 13.87; result = llround(x); cout << "llround(" << x << ") = " << result << endl; x = 50.5; result = llround(x); cout << "llround(" << x << ") = " << result << endl; x = -11.16; result = llround(x); cout << "llround(" << x << ") = " << result << endl; x = -13.87; result = llround(x); cout << "llround(" << x << ") = " << result << endl; x = -50.5; result = llround(x); cout << "llround(" << x << ") = " << result << endl; return 0; }
运行该程序时,输出为:
llround(11.16) = 11 llround(13.87) = 14 llround(50.5) = 51 llround(-11.16) = -11 llround(-13.87) = -14 llround(-50.5) = -51
#include <iostream> #include <cmath> using namespace std; int main() { int x = 15; long long int result; result = llround(x); cout << "llround(" << x << ") = " << result << endl; return 0; }
运行该程序时,输出为:
llround(15) = 15
对于整数值,应用llround函数将返回与输入相同的值。所以它在实际中并不常用来表示整数值。